(C++) ConvertVector

Convert code snippet to convert std::vector<X> to std::vector<Y> using boost::lexical_cast.


#include <vector>

#include <boost/lexical_cast.hpp>



//From http://www.richelbilderbeek.nl/CppConvertVector.htm

template <class Source, class Target>

const std::vector<Target> ConvertVector(

  const std::vector<Source>& v)

{

  const size_t sz = v.size();

  std::vector<Target> v_new(sz);

  for(size_t i=0; i!=sz; ++i)

  {

    v_new[i] = boost::lexical_cast<Target>(v[i]);

  }

  return v_new;

}

Versions that do not work

At the moment, I do not have time to get the better pieces of code to compile. Feel free to contact me if you can.


#include <algorithm>

#include <vector>

#include <boost/lexical_cast.hpp>



//From http://www.richelbilderbeek.nl/CppConvertVector.htm

template <class Source, class Target>

const std::vector<Target> ConvertVector(

  const std::vector<Source>& v)

{

  std::transform(v.begin(),v.end(),std::back_inserter(v_new),

    std::ptr_fun<Source,Target>(boost::lexical_cast<Target>()));

  return v_new;

}


#include <algorithm>

#include <vector>

#include <boost/lexical_cast.hpp>



//From http://www.richelbilderbeek.nl/CppConvertVector.htm

template <class Source, class Target>

const std::vector<Target> ConvertVector(

  const std::vector<Source>& v)

{

  std::vector<Target> v_new(v.size());

  const std::vector<Source>::const_iterator source_end = v.end();

  std::vector<Source>::const_iterator source_in = v.begin();

  std::vector<Target>::const_iterator target_out = v_new.begin();

  for( ; source_in!=source_end; ++source_in, ++target_out)

  {

    *target_out = boost::lexical_cast<Target>(*source_in);

  }

  return v_new;

}

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